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Rina8888 [55]
3 years ago
6

Which one ????????????

Mathematics
1 answer:
gregori [183]3 years ago
5 0
B is your answer because if u look at it the
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Find the product. x3(x2+5x+1)
Stella [2.4K]

Answer: x^5+5x^4+x^3


Step-by-step explanation:

assuming the expression is x^3(x^2+5x+1) each term in the bracket is multiplied by x^3

x^3(x^2+5x+1)

=(x^3*x^2)+(x^3*5x)+(x^3*1)

=x5+5x^4+x^3


4 0
4 years ago
Can someone tell me the answer
Blizzard [7]
See the photo attached for the answers

7 0
3 years ago
Please answer the following question. Also please answer if you actually know it.
Iteru [2.4K]

Given : f(x)= 3|x-2| -5

f(x) is translated 3 units down and 4 units to the left

If any function is translated down then we subtract the units at the end

If any function is translated left then we add the units with x inside the absolute sign

f(x)= 3|x-2| -5

f(x) is translated 3 units down

subtract 3 at the end, so f(x) becomes

f(x)= 3|x-2| -5 -3

f(x) is translated   4 units to the left

Add 4 with x inside the absolute sign, f(x) becomes

f(x)= 3|x-2 + 4| -5 -3

We simplify it and replace f(x) by g(x)

g(x) = 3|x + 2| - 8

a= 3, h = -2 , k = -8



5 0
3 years ago
8,11,14,17 and you have to find the 74th term
astra-53 [7]

Answer:

227 is the 74th term of your question.

7 0
3 years ago
Which of the following numbers is divisible by 3, 5, and 10?
Alex787 [66]

Answer:

D. 30

Step-by-step explanation:

A. 15

3 and 5 are liable. 10 is not

B. 20

5 and 10 liable. 3 is not.

C. 25

5 is liable. 3 and 10 is not.

D. 30

3, 5, and 10 are liable

8 0
3 years ago
Read 2 more answers
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