Answer: The 95% confidence interval is approximately (55.57, 58.43)
======================================================
Explanation:
At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.
The sample size is n = 17
The sample mean is xbar = 57
The population standard deviation is sigma = 3
The lower bound of the confidence interval is
L = xbar - z*sigma/sqrt(n)
L = 57 - 1.960*3/sqrt(17)
L = 55.5738905247863
L = 55.57
The upper bound is
U = xbar + z*sigma/sqrt(n)
U = 57 + 1.960*3/sqrt(17)
U = 58.4261094752137
U = 58.43
Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.
I cant give you the answer without the picture but I can tell you how to solve it.
if all the sides are the same length just multiply one of the numbers by the sides, for example, a rubics cube is 9 cm on each side. 9*6=54, so the answer would be 54 cm
The median for this set of data, I believe it is Team Leader. Mostly because the middle wage is Team Leader, along with the wage.
I did where you subtract 4 from both sides then divide 2 from 4 and you get 0.5 as x for your answer but im not sure
It’s either A or B but I would choose B as the correct answer
