Question

A bag contains 6 gray tiles and 3 blue tiles. Jenny reached into the bag and picked a tile

Answer 1

Answer:

The probability that Jenny picked a gray tile with her second pick given that she picked a blue tile with her first pick = 0.25

Step-by-step explanation:

i.) there are 6 gray tiles and 3 blue tiles

ii) the probability that Jenny picked a blue tile first is given by

$\frac{number\hspace{0.1cm} of \hspace{0.1cm} blue\hspace{0.1cm} tiles }{total \hspace{0.1cm}number\hspace{0.1cm} of \hspace{0.1cm}tiles\hspace{0.1cm} } = \frac{3}{9} = \frac{1}{3}$

iii) the probability that Jenny picked a gray tile with her second pick without replacing the first tile$\frac{number\hspace{0.1cm} of \hspace{0.1cm} blue\hspace{0.1cm} tiles }{total \hspace{0.1cm}number\hspace{0.1cm} of \hspace{0.1cm}tiles\hspace{0.1cm} } \times \frac{number\hspace{0.1cm} of \hspace{0.1cm} gray\hspace{0.1cm} tiles }{total \hspace{0.1cm}number\hspace{0.1cm } of \hspace{0.1cm}tiles\hspace{0.1cm} - 1 } = \frac{3}{9} \times \frac{6}{8} = \frac{1}{3} \times \frac{3}{4} = \frac{1}{4} = 0.25$

The probability that Jenny picked a gray tile with her second pick given that she picked a blue tile with her first pick = 0.25