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3 years ago

I don't understand how to solve this please help

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

PI x r^2 is the equation for the area of a circle. Clearly, we have 3 quarters of a circle here, so we can divide our answer by 4 and then multiply it by 3.

PI x 10^3 = 314.159...

Divide by 4 = 78.540...

Multiply by 3 = 235.619...

Therefore the answer is the third one.

I am Lyosha [343]3 years ago

3 0

Area=pi x radius squared so (3.14)(10)squared = 314

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The sum of the squares of two consecutive positive even integers is 52.Find the integers

ankoles [38]

Answer:

The two consecutive positive integers are $4$ and $6$ .

Step-by-step explanation:

Let $x$ be an even integer, then the next even integer is $(x+2)$ .

The sum of the squares of these even integers is $52$ .

We can write the following equation and solve for $x$ .

$x^2+(x+2)^2=52$ .

We expand to get,

$x^2+x^2+4x+4=52$ .

We simplify to get,

$2x^2+4x+4-52=0$ .

This gives us,

$2x^2+4x-48=0$

We divide through by 2 to get,

$x^2+2x-24=0$ .

This is now a quadratic trinomial

We split the middle term to get,

$x^2+6x-4x-24=0$ .

We factor to obtain,

$x(x+6)-4(x+6)=0$

$\Rightarrow (x+6)(x-4)=0$

$\Rightarrow (x+6)=0 or (x-4)=0$

$\Rightarrow x=-6 or x=4$

We discard $x=-6$ since it is not a positive integer.

$\therefore x=4$

Hence the two consecutive positive even integers are,

$4$

and

$4+2=6$

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kramer

Answer:

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Step-by-step explanation:

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2 years ago

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MaRussiya [10]

Answer:

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Find the first 4 terms of the Arithmetic sequence. f(n) = f(n-1) + 5 f(1) = -2

nexus9112 [7]

f(n) = f(n-1) + 5 simply means

the next term or f(n), will have a value of
the one before it, or f(n-1), +5

so.. you're looking for the 4th term, that means f(4)
to get 4th term then, that will be the 3rd term plus 5,
whatever the 3rd term is

now... f(1) = -2, simply means, the term 1, or f(1), or first term, is -2

now to find a term value in an arithmetic sequence $\bf f(n)=f(1)+(n-1)d\\\\
\begin{cases}
n=n^{th}\ term\to &4\\
f(1)=\textit{first term}\to &-2\\
d=
\begin{array}{llll}
\textit{common difference, or amount}\\
\textit{added to get the next term}
\end{array}\to &5
\end{cases}\\\\
-----------------------------\\\\
thus
\\\\
f(4)=f(1)+(4-1)5$

and I'm sure you know what f(1) is, so, just plug it in, to get f(4), or 4th term

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3 years ago