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2 years ago

11

Can the sides of a triangle have lengths 13, 5, and 16?

1 answer:

Alika [10]2 years ago

7 0

Answer:

Yes

Step-by-step explanation:

13 + 5 > 16
16 - 3 < 5
Yes :D

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What is the solution to the system? <br><br> (___,___)

Rina8888 [55]

For the first line we have a slope of (y2-y1)/(x2-x1)

(2--2)/(1--1)=4/2=2 so we have:

y=2x+b, now solve for b with either of the points, I'll use: (1,2)

2=2(1)+b

b=0 so the first line is:

y=2x

Now the second line:

(1-10)/(4--2)=-9/6=-3/2 so far then we have:

y=-3x/2+b, using point (4,1) we solve for b...

1=-3(4)/2+b

1=-6+b

b=7 so

y=-3x/2+7 or more neatly...

y=(-3x+14)/2

...

The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...

2x=(-3x+14)/2

4x=-3x+14

7x=14

x=2, and using y=2x we see that:

y=2(2)=4, so the solution occurs at the point:

(2,4)

6 0

3 years ago

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Hoochie [10]

Answer:

c

Step-by-step explanation:

6 0

2 years ago

Peter will travel 1,342 kilometers from Paris to Rome. Peter will start his journey at 5:00 A.M. Monday morning and arrive in Ro

Hunter-Best [27]

Answer:

61 km/s

Step-by-step explanation:

First, you count the number of hours he travelled: 22

Next, divide the distance he travelled, 1342, by the time he travelled, 22, $\frac{1342}{22} = 61$

7 0

2 years ago

Plz help.. btw this is 7th grade math. (22 pts.)

belka [17]

Answer:

He needs 4 1/3 buckets of fish.

Step-by-step explanation:

140 - 75 = 65 pounds of fish left to eat

15x = 65

x = 65 / 15

x = 4 1/3 buckets of fish left to eat

6 0

3 years ago

One angle of a triangle measures <img src="https://tex.z-dn.net/?f=10degrees" id="TexFormula1" title="10degrees" alt="10degrees"

iVinArrow [24]

Answer:

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$

Step-by-step explanation:

Let

x ----> the measure of one angle of the triangle

y ---> the measure of the second angle

z ----> the measure of the third angle

we know that

The sum of the measure of the interior angles in any triangle must be equal to 180 degrees

$x+y+z=180^o$ -----> equation A

One angle of a triangle measures 10 degrees more than the second

$x=y+10$ ----> equation B

The measure of the third angle is twice the sum of the first two angles

$z=2(x+y)$ ---> equation C

substitute equation B in equation C

$z=2(y+10+y)$

$z=4y+20$ ----> equation D

substitute equation D and equation B in equation A

$(y+10)+y+(4y+20)=180^o$

solve for y

$6y=180-30\\6y=150\\y=25^o$

Find the value of x

$x=25+10=35^o$

Find the value of z

$z=4(25)+20=120^o$

therefore

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$

5 0

3 years ago