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3 years ago

I don’t understand how to solve this problem. Please help, with steps.

Mathematics

1 answer:

sveta [45]3 years ago

3 0

I'll help you in the comments of this questions. need time to work it out.

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What is 63/80 as a decimal

Kaylis [27]

To get 63/80 converted to decimal, you simply divide 63 by 80. Don't worry. You don't need to get the calculator out, because I did this for you.

63/80 as a decimal is:

<span>0.787500</span>

7 0

3 years ago

If the circle below is cut from the square of plywood below, how many square inches of plywood would be left over? Use π = 3.14,

Elis [28]

Answer:

86in²

Step-by-step explanation:

Find the complete question attached

Area of the circle = πr²

Area of the square = L²

Length of the side of the square

r is the radius of the circle

r = L/2 = 20/2 =10in

Given

Length of the side of the circle = 20in

Area of the square = 20²

Area of the square = 400in²

Area of the circle =π(10)²

Area of the circle = 3.14(100)

Area of the circle= 314in²

Amount of plywood left over = 400in²-314in² = 86in²

8 0

3 years ago

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

3 years ago

a plumber laying 500 meters of drain pipe required 20 men of working for 10 days . What length in meters would be laid by 50 men

belka [17]

Answer:

500 meters =20men =10days

To get the factor 500/(20*10)= 5/2 meters/day

For 50 men and 5days we don't know the meters

So we go by 50*(5/2)*5 =625meters

8 0

3 years ago

Which of the following is a list of all the possible outcomes with 2 or 3 heads?

Galina-37 [17]

Answer:

Step-by-step explanation:

5 0

3 years ago