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mojhsa [17]
3 years ago
11

Plzzzz its due in 15mins1.

Mathematics
1 answer:
BigorU [14]3 years ago
5 0
P = -3
m = -22
p = 4
n = -9
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Estimate 25.65 + 13.23 + 6.35 by rounding each number to the nearest tenth.
sergij07 [2.7K]

Answer:

  • b. 25.7 + 13.2 + 6.4 = 45.3

Step-by-step explanation:

25.65 ≈ 25.7, 13.23 ≈ 13.2, 6.35 ≈ 6.4

  • 25.65 + 13.23 + 6.35 =
  • 25.7 + 13.2 + 6.4 =
  • 45.3

Correct choice is b.

5 0
2 years ago
I will give BRAINLIEST to whoever is correct.
attashe74 [19]
28/11.2 = 2.5

since they are similar and openly stated as parrallelograms, you know that they have a scale of the longest edge of EFGH to the longest edge of JKLM
5 0
3 years ago
Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx
Feliz [49]
Your question seems a bit incomplete, but for starters you can write

\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}

Expanding where necessary, recalling that (1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x, you have

\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x

Now, since 1+\tan^2x=\sec^2x, the final form could also take

\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1

or

\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x
7 0
3 years ago
Help please <br> Brainiest answer to whoever is first <br> Show work if you can
aalyn [17]

Answer:

114

Step-by-step explanation:

19x6=114

6 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B8ux%5E%7B5%7D%20%7D%20%5Csqrt%7B2ux%7D" id="TexFormula1" title="\sqrt{8ux^{5} } \sqr
lozanna [386]

Answer:

4ux³

Step-by-step explanation:

√8ux⁵ √2ux

√8*2 u*u x⁵*x

√16u²x⁶

4ux³

3 0
2 years ago
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