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Verdich [7]
3 years ago
5

Divide.

Mathematics
1 answer:
kakasveta [241]3 years ago
6 0
C. 17 r 1 is the correct answer
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What is 4/16 ÷ 3/4 ​
Kobotan [32]

Answer:

4/12 simplified to 1/3.

Step-by-step explanation:

4/16 x 4/3 = 4/12

4/12 = 1/3

5 0
2 years ago
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Trayvon bought 2 gallons of milk at the supermarket how many quarts of milk did he buy
Natalka [10]

Answer: He bought 8 quarts

Step-by-step explanation:

There are 4 quarts in a gallon so if you multiply 4 by 2 then you get 8,

4 0
3 years ago
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The Temperature at 5:00 A.M. Is -38 F. The temperature rises 20 by 11:00 A.M. Use addition to find the temperature at 11:00 A.M.
GarryVolchara [31]
-38F + 20F equals -18F
8 0
3 years ago
Will mark brainliest for full answer
Svet_ta [14]

Answer:

y=2

Step-by-step explanation:

Hope it helps

5 0
3 years ago
It is known that diskettes produced by a cer- tain company will be defective with probability .01, independently of each other.
zheka24 [161]

Answer:

1.27%

Step-by-step explanation:

To solve this problem, we may consider a binomial distribution where a customer can either accept or reject (and return) the diskette package.

Lets consider  some aspects:

1. From the formulation of the exercise we know that a package is accepted if it has at most 1 defective diskette. So our event A is defined as:

A = 0 or 1 defective diskette

2. The probability of a diskette being defective is 0.01

3. Each package contains 10 diskettes.

If X is defined as number of defective diskettes in the package, the probability of X is given by a binomial distribution with probability 0.01 and n=10

X ~ Bin(p=0.01, n=10)

Let us remember the calculation of probability for the binomial distribution:

P(X=x)=nCx*p^{x}*(1-p)^{(n-x)} with x = 0, 1, 2, 3,…, n

Where

n: number of independent trials

p: success probability  

x: number of successes in n trials

In our case success means finding a defective diskette, therefore

n=10

p=0.01

And for x we just need 0 or 1 defective diskette to reject the package

Hence,

P(X=x)=10Cx*0.01^{x}*(1-0.01)^{(10-x)} with x = 0, 1

So,

P(A)=P(X=0)+P(X=1)

P(A)=10C0*0.01^{0}*(1-0.01)^{(10-0)} + 10C1*0.01^{1}*(1-0.01)^{(9)}

P(A)=0.99^{10}+10*0.01*0.99^{9}

P(A)=0.9957

Now, because we have 3 packages and we might reject just 1 of them, we can find this probability like this:

3*(1-P(A))*P(A)*P(A) = (1-0.9957)*0.9957*0.9957=0.0127

Finally, we have that the probability of returning exactly one of the three packages is 1.27%

3 0
3 years ago
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