Answer:55
Step-by-step explanation:
55
I'm pretty sure its line c.
Step-by-step explanation:
Answer:
The best point of estimate for the true mean is:

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Step-by-step explanation:
Information given
represent the sample mean for the late time for a flight
population mean
represent the population deviation
n=76 represent the sample size
Confidence interval
The best point of estimate for the true mean is:

The confidence interval for the true mean is given by:
(1)
The Confidence level given is 0.95 or 95%, th significance would be
and
. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got
Replacing we got:
Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Initial balance, I = $2376.10 .
Total amount of purchase made, A = $( 875.22+65.75+45.22+21.23 ) = $1007.42 .
Total amount credit, c = $875.22 .
Fine, f = $45.30 .
Another purchase,
.
So, balance left is :
B = I - A - f - a + c
B = 2376.10 - 1007.42 - 45.30 - 59.4025 + 875.22
B = $2139.1975
Hence, this is the required solution.
Associative,commutative and distributive