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lidiya [134]
3 years ago
14

The line plot shows the weight gain, in pounds, of several dogs seen on Monday by a veterinarian at the animal clinic. A number

line with one x above .5, one x above 1.5, one x above 2, one x above 3, two xs above 3.5, two xs above 4, one x above 4.5, and one x above 8.5. How many dogs gained fewer than 3 lb? Enter your answer in the box.
Mathematics
2 answers:
denis-greek [22]3 years ago
6 0

Answer:

3 x's

Step-by-step explanation:

Lerok [7]3 years ago
3 0
There were 3 dogs that gained fewer than 3 pounds.

Counting the number of x's marked above numbers less than 3, we can see that there are 3 x's.
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The swimming pool is opening hours a day the pool manager must divide pool time equally among five groups camp; camp swim team,
ale4655 [162]

Answer:

1.6 hours

Step-by-step explanation:

Number of opening hours a day = 8

Number of groups = 5

Dividing the number of opening. Hours equally among the 5 groups :

8 hours / 5

= 1.6 hours per group per day

4 0
3 years ago
Perez’s Ski Shop made a profit of $32,000 last year. This year, the profits are 250 percent of last year’s profits. How much of
Tanzania [10]

Answer:

$80,000 I think is right

3 0
3 years ago
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Answer for brainliest!!! :> Three hens can lay 3 eggs in 3 days. How many hens would lay 3 eggs in 9 days?
marta [7]

It would still be the same 3 hens in 9 days.

6 0
2 years ago
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A company’s profit in dollars is modeled by the equation p(x) = –0.5x2 + 100x, where x represents the number of units sold.
serg [7]

Answers:

a. The company needs to sell 100 units to reach the maxmum profit.

b. The company's maximum profit is $5,000.

Solution:

a. How many unit does the company need to sell to reach the maximum profit?

p(x)=-0.5x^2+100x

This is a quadratic equation, and its graph is a parabola vertical (because the veriable "x" is square). Comparing with the general form:

p(x)=ax^2+bx+c; a=-0.5, b=100, c=0

a=-0.5<0 (negative), then the parabola opens downward, and it has a maximimun value (maximum profit) at its vertex.

We can find the abscissa of the vertex (units that the company needs to sell to reach the maximum profit using the following formula:

x=-b/(2a)

Replacing b by 100 and a by -0.5 in the formula above:

x=-100/[2(-0.5)]

x=-100/(-1)

x=100

The company needs to sell 100 units to reach the maximum profit.


b. What's the company's maximum profit?  

To determine the maximum profit we substitute the value of "x" obrained in part "a" in the quadratic equation:

x=100→p(100)=-0.5(100)^2+100(100)

p(100)=-0.5(10,000)+10,000

p(100)=-5,000+10,000

p(100)=5,000

The company's maximum profit is $5,000.

6 0
3 years ago
Find the midpoint of the line segment.
Alik [6]

Answer:

(1, 3)

Step-by-step explanation:

The first endpoint (the one on the left) is (-3, 2). The second endpoint (the one on the right) is (5, 4). To find the midpoint, find the middle of both x and y. To do that, add the values of x and y respectively and divide by 2:

for x-value of midpoint:

(x-value of first endpoint + x-value of second endpoint) / 2

= (-3 + 5) / 2

= 2 / 2

= 1

for y-value of midpoint

(y-value of first endpoint + y-value of second endpoint) / 2

= (2 + 4) / 2

= 6 / 2

= 3

8 0
3 years ago
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