Answer:
We can find the critical value 
And for this case if the confidence increase the critical value increase so then this statement is True
Step-by-step explanation:
For a confidence level given c, we can find the significance level like this:
And with the degrees of freedom given by:
We can find the critical value
And for this case if the confidence increase the critical value increase so then this statement is True
To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
2/3 n = -12 Write equation
(3/2) 2/3n = -12/1 (3/2) Isolate n
n = -36/2 Simplify
n = -18 Answer
Answer: angle 2 is supplementary to angle 1
Answer:
4dogs and no wolves
Step-by-step explanation:
when a dog is taken care of (Trained) it could be let to run free in a definite region.
On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.
If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.
But for Wolves from the question it is deduced that: A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.
With these two, wolves wont be allowed on the plane at all.
