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OLEGan [10]
3 years ago
14

En una carrera de autos compiten William, José, Lucas, Oscar e Iván. Quien acierte los dos primeros lugares, en cualquier orden,

ganara el doble de lo que apueste. Quien acierte el orden correcto ganara tres veces el valor apostado. Construir el espacio muestral con las posibles posiciones de la carrera.
Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0
Do you speak english
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HELP ME PLEASE⚠️ the question is in the picture
Pavlova-9 [17]

Answer:

Answer is 3

Step-by-step explanation:

Because the Perimeter is true and area is true.

6 0
3 years ago
Find the sum and simplify the following expressions. <br> (s + 12) + (3s – 8)
nika2105 [10]

Answer:

4(s+1)

Step-by-step explanation:

(s+12) + (3s -8)

s+12+(3s-8)

s+12+3s-8

4s+12-8

4s+4

4(s+1)

8 0
2 years ago
Find the size of the marked angles​
morpeh [17]

Answer:

b = 55°

c = 35°

Step-by-step explanation:

b° = 180° - (85°+40°) = 180° - 125° = 55°

c° = 180° - (b°+90°) = 180° - (55°+90°) = 180° - 145° = 35°

3 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-9, -9) −6,−12)?
Fed [463]

Answer:

m = -1

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

Therefore,

slope = (-12-(-9))/(-6-(-9))

= -3/3

=-1

8 0
3 years ago
The altitude of a triangle is increasing at a rate of 1 cm/ min while the area of the triangle is increasing at a rate of 2 cm2
serg [7]
Ya, calculus and related rates, such fun!




everything is changing with respect to t

altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min

area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min

base=db/dt

alright

area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt

ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b

so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min

therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt

the base is decreasing at 1.6cm/min
4 0
3 years ago
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