altitude rate will be dh/dt and that is 1cm/min dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min da/dt=2cm²/min
base=db/dt
alright
area=1/2bh take dervitivie of both sides da/dt=1/2((db/dt)(h)+(dh/dt)(b)) solve for db/dt distribute da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b) move da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h) times 2 both sides 2da/dt-(dh/dt)(b)=(db/dt)(h) divide by h (2da/dt-(dh/dt)(b))/h=db/dt
ok we know height=10 area=100 so a=1/2bh 100=1/2b10 100=5b 20=b
As a group they were paid $1000 after putting in 4+6+5+5 = 20 worker-hours. $1000/(20 worker-hours) = $50/(worker-hour) Alemu received 4*$50 = $200 Tulu received 6*$50 = $300 Kassa and Tegitu each received 5*$50 = $250
