Question

a triangle has the following side lengths: x-2,x, and 3x+1. another triangle has the following side lengths: 2x-5, x+4, 6x-7. of the perimeters of the two triangles are equal, what is x?

Answer 1

Perimeter is the addition of all the sides
x-2+x+3x+1=2x-5+x+4+6x-7; since their perimeters are equal
5x-1=9x-8
collect the like terms
-1+8=9x-5x
7=4x
x=7/4
x=1.75