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Anestetic [448]
3 years ago
8

Can someone please help me.......

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0
Point -2,-1 would change to -2,0. the area of the new rectangle is 10 square units
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I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr
Illusion [34]

Answer:

<h2><u>question 1</u></h2>

n^{2} - 20n -96 = 0

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u />x^{2} + 12 x = 48<u />

in the form ax^{2}  +bx +c = 0

= x^{2} +12x - 48

make use of the formula :

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

replace values to make 2 equations :

1.\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1} = 3.17

2.\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1} = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u />x^{2} -14x+40=0<u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

<u />5b^{2} -20b-18 = 7<u />

in the form ax^{2}  +bx +c = 0

this becomes 5b^{2} -20b-18-7

= 5b^{2} -20b-25

can simplify by 5

= b^{2} -4b-5 =0\\

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0
4 years ago
Read 2 more answers
Please help this is due, not sure if I did this right. Triangle ABC is shown below with vertices A (7,4), B(1,1), and C(9,0). Fi
Paha777 [63]

i think u did it right

5 0
3 years ago
What's the perimeter of this shape?​
Strike441 [17]

Answer:

It is 20m.

Step-by-step explanation:

The perimeter equals the sum of all the sides. So 5+7+3+4+1

7 0
3 years ago
9.<br> Write an<br> equation perpendicular to y = 2x + 6<br> that passes through the point (8,4).
Sidana [21]

Answer:

y=-1/2x+8

Step-by-step explanation:

Perpendicular of y=2x+6 is y=-1/2x

Substitute coordinates

4=-1/2(8)+8

y=-1/2x+8

8 0
3 years ago
Find the solution set to each inequality. Express the solution in set notation.
daser333 [38]

The solution to the inequality 6m + 2 > -27 is  m > -4.33

The solution to the inequality 8(p-6)>4(p-4) is  p > 8

The given inequality is:

6m  +  2  >  - 27

Subtract 2 to both sides of the inequality

6m  +  2 - 2  >  -27  -  2

6m   >  -29

Divide both sides by 6

\frac{6m}{6}> \frac{-29}{6}  \\m  > \frac{-29}{6}\\m > -4.83

For the inequality  8(p-6)>4(p-4)

Expand the inequality using the distributive rule

8p  -  48   >  4p  -  16

Collect like terms

8p  -  4p  >  -16  +  48

4p    >  32

Divide both sides of the inequality 4

\frac{4p}{4} > \frac{32}{4}\\p > 8

The solution to the inequality 6m + 2 > -27 is m > -4.33

The solution to the inequality 8(p-6)>4(p-4) is p > 8

Learn more here: brainly.com/question/15816805

3 0
3 years ago
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