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skelet666 [1.2K]
3 years ago
14

Can someone explain how to do this and the answer?

Mathematics
1 answer:
inysia [295]3 years ago
7 0

Step-by-step explanation:

Helo

your answer refer to the attachment

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Oranges cost 25 cents for 1/2 kilograms. How much would 8 kilograms of oranges cost?
eimsori [14]
\dfrac{1}{2} \text{ kg} \longrightarrow 25 \text{ cents}

Find 1 kg:
1 \text{ kg} \longrightarrow 25 \times 2 \text{ cents}

1 \text{ kg} \longrightarrow 50 \text{ cents}

Find 8 kg:
8\text{ kg} \longrightarrow 50 \times 8 \text{ cents}

8\text{ kg} \longrightarrow 400 \text{ cents or } \$4.00

Answer: 8 kg of oranges cost $4.00

6 0
3 years ago
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What is the least common mutliple of 10 and 12?
GalinKa [24]

Answer:

2

Step-by-step explanation:

You can divide both of them by 2

3 0
3 years ago
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What is the slope intercept equation for thus line?
sveticcg [70]

Answer:

y= 2/3 x + 4

y- intercept= (0,4)

and slope of the line is 2/3

6 0
3 years ago
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Write an equation for the translation of x^2+y^2=49 by 3 units left and 4 units up
ludmilkaskok [199]
\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}\\\\
-----------------------------\\\\
x^2+y^2=49\iff (x-0)^2+(y-0)^2=7^2\quad 
\begin{cases}
h=0\\
k=0
\end{cases}
\\\\\\
(x-\underline{(-3)})^2+(y-\underline{(+4)})^2=7^2\quad 
\begin{cases}
h=-3\\
k=4
\end{cases}
\\\\\\
\boxed{(x+3)^2+(y-4)^2=49}
5 0
3 years ago
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A company purchased a delivery van for $28,000 with a salvage value of $3,000 on September 1, Year 1. It has an estimated useful
Tems11 [23]

Answer:

Depreciation till December 31, Year 1 will be equal to 1,250$

Step-by-step explanation:

Purchasing Cost = 28,000$

Salvage Value = 3,000$

Total Depreciation:

Total Depreciation over 5 years (60 Months) = Purchasing Cost - Salvage Value

Total Depreciation over 5 years (60 Months) = 28,000 - 3,000

Total Depreciation over 5 years (60 Months) = 25,000$

Monthly Depreciation:

Using the unity method we have monthly depreciation by dividing the total depreciation by the total no. of months as below:

Total Depreciation over a single month =25,000/60

Total Depreciation over a single month = 416.67$ (Monthly Depreciation)

Depreciation till December 31, Year 1

As from September 1, Year 1 to December 31, Year 1, its been 3 months therefore total depreciation will be = 3 * Monthly Depreciation

Depreciation till December 31, Year 1 = 3 * 416.67

Depreciation till December 31, Year 1 = 1,250$

4 0
3 years ago
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