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yuradex [85]
3 years ago
14

The table compares the daily average temperature in a park (in degrees Celsius) and the number of people who visited the park th

at day. Can the number of people who visited the park be represented as a function of the daily average temperature?

Mathematics
2 answers:
lions [1.4K]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

Simora [160]3 years ago
7 0

Answer:

YES, the number of people who visited the park can be represented as a function of the daily average temperature.

Step-by-step explanation:

From the table of values given which defines the number of visitors to the park as a function of daily temperature, the temperature is the domain values (independent variable), while the number of visitors is the range values (dependent variable).

For any relation to be considered a function, as a principle, any given domain value must have exactly one range value. In other words, there must not be two different range values assign to one domain value.

This means, for the relation between temperature and number of visitors to be considered a function, it must not have a domain value that is mapped to more than one range value.

Examining the table given, if we map each domain value to the range value, we will find out that there are only 1 exact range value for a domain value.

<em>Therefore, we can say: YES, the number of people who visited the park can be represented as a function of the daily average temperature.</em>

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7. A crate of soft drinks contains 9 bottles of coke, 6 bottles of pepsi and 4 bottles of limca. Ademola picks one bottle of sof
Mekhanik [1.2K]

The probability that the events (a) they both picked Limca = 0.04, (b) Ademola only picked Pepsi = 0.32, (c) They both picked the same brand = 0.33 (d) They picked different brand=0.67.

<h3>What is probability?</h3>

Probability is the fraction of the required outcome event divided by the number of possible outcomes of events.

Total possible outcome of the event of picking drinks contained in the crate = 19

Hence, we can compute the following as follows;

(a) The probability they both picked Limca = (4/19)×(3/18)

Limca = 12/342

Limca = 0.04

(b) The probability Ademola only picked pepsi = 6/19

pepsi = 0.32

(c) The probability they both picked the same brand = (9/19)×(8/18)+(6/19)×(5/18)+(4/19)×(3/18)

=(72+29+12)/342

= 114/342

= 0.33

(d) The probability they picked different brand = (9/19)×(6/18)+(9/19)×(4/18)+(6/19)×(9/18)+(6/19)×(4/18)+(4/19)×(9/18)+(4/19)×(6/18)

The probability they picked different brand = (54+36+54+24+36+24)/342

The probability they picked different brand = 228/332

The probability they picked different brand = 0.67

Therefore, the probability for events (a) is 0.04, (b) is 0.32, (c) is 0.33 and (d) is 0.67.

Know more about probability here: brainly.com/question/24830485

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