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Elanso [62]
3 years ago
8

Can anyone please help with this.

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0
The first question answer is 21*10^7
The second question answer is 5*10^2
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A set of math tests is normally distributed
sergey [27]

2.2-0.6=1.6

1.6*81=129.6

129.6/2=64.8

Answer: 64.8

3 0
3 years ago
1/2 cm x 3/2cm x 7/4cm... Find the volume
forsale [732]
Remember, to the find the volume, you have to do length*width*height.

So it would be 7/4 * 3/2 * 1/2

To answer this, multiply all the numerators together, and multiply all the denominator together.

This would be:

21/16



So the answer is 21/16 cm^3 or 1.3125 cm^3.


Hope this helps. If you have any questions, place it in the comment section below.


6 0
3 years ago
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
sdas [7]

Answer:

a

    n=  75, 582

b

  n=    2300

c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
3 years ago
ALOT OF POINTS IF YOU HELP ME PLEASE EXPLAIN ​
Svetllana [295]

Answer:

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).

Step-by-step explanation:

Misha's group was asked to write an expression equivalent to  

7y²z + 3yz² - 3

When Mr. Chen checked their answers, he found only one to be correct.

And she was Helena.

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).  

Because, (7y²z + 6yz²- 5 - 3yz² + 2)

= 7y²z + (6yz² - 3yz²) - (5 - 2)  

= 7y²z + 3yz² - 3 (Answer)

4 0
3 years ago
What is the equation of the circle with center (0, 0) that passes through the point (-8, 3)?
77julia77 [94]

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is :  x² +y² = 73</span></span>

7 0
3 years ago
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