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fgiga [73]
3 years ago
9

The legs of a right triangle are 10 centimeters and 24 centimeters long. What is the length of the hypotenuse?

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0
A² + b² = c²

Where a and b are the legs and c is the hypotenuse

So, plug in 10 for one of the legs and 24 for the other leg

c will be left blank because that is what you are trying to find, the hypotenuse

10² + 24² = c²

100 + 576 = c²

676 = c²

Take the square root of both sides of the equation to isolate c

√676 = √c²

Square of c and the square root cross out on the right

Take the square root of 676

c = 26

So, the length of the hypotenuse is 26 centimeters




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Answer:

c(1+2+4+5) =1

c =\frac{1}{12}

Now we can find the expected value with this formula:

E(Y) =\sum_{i=1}^n Y_i P(Y_i) =\sum_{i=1}^n cy_i *y_i = cy^2_i

And replacing we got:

E(Y) = \frac{1}{12} (1^2 + 2^2 + 4^2 +5^2) = \frac{46}{12}= \frac{23}{6}

Step-by-step explanation:

For this case we know the following probability mass function given:

P(y) = cy , y= 1,2,4,5

For this case we need to satisfy the following condition in order to have a probability distribution function:

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And we have this:

c(1+2+4+5) =1

c =\frac{1}{12}

Now we can find the expected value with this formula:

E(Y) =\sum_{i=1}^n Y_i P(Y_i) =\sum_{i=1}^n cy_i *y_i = cy^2_i

And replacing we got:

E(Y) = \frac{1}{12} (1^2 + 2^2 + 4^2 +5^2) = \frac{46}{12}= \frac{23}{6}

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