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Leona [35]
3 years ago
11

A number decreased by the product of 6 and 3

Mathematics
2 answers:
Brut [27]3 years ago
7 0

Answer:

n-(6*3)

Step-by-step explanation:

a number which is not given so you could use any variable(N).

to decrease means to subtract. the product means multiplication.

so the product of (6*3) decreased from a number (N).

n-(6*3)

saw5 [17]3 years ago
4 0

Answer:

nine

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3 years ago
6cos(20πt-π)+6√3cos(20πt-π\2)
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<u>Answer</u><u> </u><u>is</u><u> </u><u>-</u><u>6</u><u>t</u>

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{ \tt{ = (6 \cos(20\pi t)  \cos(\pi)  +  6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t)  \cos( \frac{\pi}{2} )  +  \sin(20\pi t)   \sin( \frac{\pi}{2} )) }} \\  = { \tt{ (- 6t + 0) + (0 + 0)}} \\  = { \tt{ - 6t}}

Note that π is 180°

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