Answer:
6 goes on top of 3
4.5 goes under 9
Step-by-step explanation:
its self-explanatory
It should be b but i don’t have paper with me so i’m not sure
What you need to do is find the greatest amount (1) and the lowest amount (1/4) of sap collected and the find how many times the lowest can go into the greatest. (So how many times can 1/4 go into 1). I believe that this is how you would do that.
Answer: Eric: The 10 is the initial amount, the 1/2 is the decay factor or the rate at which it decreases, and the exponent w is the number of weeks it decreases by factor 1/2, or the time. Andrea, 1 is the initial amount, 0.2 is the decay factor or rate of decrease, w is time passed or number of weeks it's decayed by the factor.
Step-by-step explanation: Answer is explanation
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
