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3 years ago

What is 217.33 rounded to the nearest tenth

Mathematics

2 answers:

jeka943 years ago

6 0

217.30 is your answer

DENIUS [597]3 years ago

4 0

217.3 hope its helpful for you

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Solve the following:<br> a) 4x 3= 2x + 7<br><br> b) 2x+6= 7x14

nikdorinn [45]

<h2><u>Correct question</u> : 4x - 3 = 2x + 7 </h2>

<h2><u>Solution</u> : 4x - 3 = 2x + 7 </h2>

$4x - 2x = 7 + 3 \\ \\ 2x = 10 \\ \\ x = \frac{10}{2} \\ \\ x = 5.$

<h2><u>Correct Question</u> : 2x + 6 = 7x - 14</h2>

<h2><u>Solution</u> : 2x + 6 = 7x - 14</h2>

$2x - 7x = - 14 - 6 \\ \\ - 5x = - 20 \\ \\ x = \frac{20}{5} \\ \\ x = 4.$

7 0

2 years ago

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irinina [24]

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2 years ago

Expand (2x + 3)^5 using the Binomial Theorem and Pascal’s triangle. Show all steps.

kari74 [83]

Answer:

32x⁵ + 240x⁴ + 720x³ + 1080x² + 810x + 243

Step-by-step explanation:

(2x + 3)⁵

₅C₀ (2x)⁵ (3)⁰ + ₅C₁ (2x)⁴ (3)¹ + ₅C₂ (2x)³ (3)² + ₅C₃ (2x)² (3)³ + ₅C₄ (2x)¹ (3)⁴ + ₅C₅ (2x)⁰ (3)⁵

Use Pascal's triangle to find nCr.

$\left\begin{array}{c}1\\1\ 1\\1\ 2\ 1\\1\ 3\ 3\ 1\\1\ 4\ 6\ 4\ 1\\1\ 5\ 10\ 10\ 5\ 1\end{array}\right$

1 (2x)⁵ (3)⁰ + 5 (2x)⁴ (3)¹ + 10 (2x)³ (3)² + 10 (2x)² (3)³ + 5 (2x)¹ (3)⁴ + 1 (2x)⁰ (3)⁵

(2x)⁵ + 15 (2x)⁴ + 90 (2x)³ + 270 (2x)² + 405 (2x)¹ + 243

32x⁵ + 240x⁴ + 720x³ + 1080x² + 810x + 243

7 0

3 years ago

Ron used 121 congruent equilateral triangles with 2 cm side lengths to form one large equilateral triangle. What is the perimete

Pepsi [2]

The number of smaller triangles along one side of the larger triangle is the square root of the total number of triangles. The perimeter of the large triangle is ...
3*(2 cm)*√121 = 66 cm

5 0

3 years ago

Help please very much

Norma-Jean [14]

Answer:

Step-by-step explanation:

3 0

2 years ago