Answer:
I thought if you try to do an exponent on a zero, then the answer would always be undefined...
Step-by-step explanation:
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Answer:
Step-by-step explanation:
To obtain the standard form of the equation of the parabola y=2(x+4)^2-7, first perform the indicated operations:
y = 2[x^2 + 8x + 16 - 7], or
y = 2[x^2 + 8x + 9],
or y = 2x^2 + 16x + 18
None of the given possible answers match. The fourth one, D, is closest to the above result, differing only in the constant term (25 versus 18).
Answer:
they are called constants. they don't have a variable on them, so their value throughout the problem will remain the same or constant.
Step-by-step explanation:
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