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Citrus2011 [14]
3 years ago
14

Please help me

Mathematics
2 answers:
bazaltina [42]3 years ago
6 0

Question-


multiply   -----    (4x^2+7x)(5x^2-3x)


A. 20^4+23x^3-21x^2


B. 20x^4+35x^2-21x


C. 20x^4+35x^3-21x^2


D. 20x^4+23x^2-21x


Answer-

A. 20^4+23x^3-21x^2


Hope i helped have a wonderful day...

Sphinxa [80]3 years ago
4 0

Answer:

A. 20^4+23x^3-21x^2

Step-by-step explanation:

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Step-by-step explanation:

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Answer: 1 over y 2 over x

Step-by-step explanation:

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2 years ago
If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal
lorasvet [3.4K]

Answer:

a

   The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

b

   The probability is  P(Z >  2.5 ) =  0.0062097

Step-by-step explanation:

From the question we are told that

        The  population mean is  \mu =  800

        The  variance is  var(x) =  1600 \ kg

        The  range consider is  x_1 =  778 \ kg  \  x_2 =  834 \ kg

         The  value consider in second question is  x =  900 \ kg

Generally the standard deviation is mathematically represented as

        \sigma =  \sqrt{var (x)}

substituting value

        \sigma =  \sqrt{1600}

       \sigma = 40

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       P(x_1 <  X <  x_2 ) =  P( \frac{x_1 -  \mu }{\sigma} <  \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma }   )

    Generally  \frac{X - \mu }{ \sigma } = Z (standardized \  value  \  of  \  X)

So

      P(x_1 <  X <  x_2 ) =  P( \frac{778 -  800 }{40} < Z< \frac{834 - 800 }{40 }   )

      P(x_1 <  X <  x_2 ) =  P(z_2 < 0.85) -  P(z_1 <  -0.55)

From the z-table  the value for  P(z_1 <  0.85) =  0.80234

                                            and P(z_1 <  -0.55) =   0.29116  

So

             P(x_1 <  X <  x_2 ) =   0.80234 - 0.29116

             P(x_1 <  X <  x_2 ) =   0.51118

The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             P(X > x ) =  P(\frac{X - \mu }{\sigma }  > \frac{x - \mu }{\sigma } )

substituting values

             P(X > x ) =  P( \frac{X - \mu }{\sigma }  >\frac{900 - 800 }{40 }   )

             P(X > x ) =  P(Z >2.5   )

From the z-table  the value for  P(Z >  2.5 ) =  0.0062097

 

7 0
3 years ago
Using the compensation strategy. 4,153+2,988
makvit [3.9K]
4,153+2,988
-12 +12
4,141+3,000

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5 0
3 years ago
Multiply.
prohojiy [21]

Answer:

D. 3x² + 19x - 14

Step-by-step explanation:

Use FOIL to find the answer.

First: x * 3x = 3x²

Outer: -2 * x = -2x

Inner: 3x * 7 = 21x

Last: 7 * -2 = -14

Form the equation:

3x² - 2x + 21x - 14

Combine like terms.

3x² + 19x - 14

8 0
3 years ago
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