Answer:
2.5
Step-by-step explanation:
The predicted regression equation is
y^=10+0.9x
where y= final exam score and x=first test score.
Also, we are given that Carla's final exam score y is 98 and Carla's first test score x is 95. We have to find residual for Carla.
Residual=Observed -predicted=y-y^
y^=10+0.9x
We know that Carla's first test score=x=95.
So,
y^=10+0.9(95)
y^=10+85.5
y^=95.5
Residual for Carla=y-y^=?
We know that Carla's final exam score=y=98.
So,
Residual for Carla=98-95.5=2.5
I would describe the constant rate of change but where is the question for the picture please apply the picture or the questions I can answer thank you have a nice day
Answer:
<h3>29 and 32</h3>
Step-by-step explanation:
Let x = number
Let y = second number
We know that there are two true equations from this. Here is shown below the equations.
x + y = 61
x + 3 = y
We could use the substitution method for finding the numbers. After that, we continue on to solve to find the first number.
x + (x+3) = 61
2x + 3 = 61
2x = 58
2x/2 = 58/2
x = 29
Now that we know that the first number is 29, plug it in to the second equation to find the second number.
x + 3 = y
29 + 3 = y
y = 32
Proof that these numbers are the correct answer:
32 + 29 = 61
61 = 61 (Which is true!)
To support me, please give me the brainliest answer. It would be greatly appreciated. Thank you!
B2]=[2−3+6√57]
Answer: ∠ACB ≅ ∠E'C'D'; translate point D' to point B
Step-by-step explanation:
That is just my best guess.
