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nignag [31]
2 years ago
14

The graph of f(x) =sqrt of x is reflected across the x-axis and then across the y-axis to create the graph of function g(x). Whi

ch statements about the functions f(x) and g(x) are true? Check all that apply. The functions have the same range. The functions have the same domains. The only value that is in the domains of both functions is 0. There are no values that are in the ranges of both functions. The domain of g(x) is all values greater than or equal to 0. The range of g(x) is all values less than or equal to 0.

Mathematics
2 answers:
pickupchik [31]2 years ago
7 0

The original function is

f(x)=√x

As this is condition for √x function, x≥ 0

So,

Domain= [0, infinity)

Range= [0, infinity)


After the reflection across x-axis and y-axis, we get a function,

g(x)=-√-x

-x≥ 0 means x≤ 0,

So,

Domain= (-infinity, 0]

Range= (-infinity, 0]


From this you can see that

-The only value that is in the domains of both functions is 0.

-The range of g(x) is all values less than or equal to 0.


only these points are correct and all other points are wrong.


See the attached graphs for both functions.



Marina CMI [18]2 years ago
5 0

Answer:


Step-by-step explanation:

actually it is The only value that is in the domains of both functions is 0.

and The range of g(x) is all values less than or equal to 0.

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Nonamiya [84]

Answer:

1) The simplified radical form is  \sqrt{36x^2}=6x

2) The simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) The simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) The simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

Step-by-step explanation:

1) Given expression is \sqrt{36x^2}

To find the simplified radical form of the given expression :

\sqrt{36x^2}

=\sqrt{36\times x^2}

=\sqrt{36}\times \sqrt{x^2}

=\sqrt{6\times 6}\times \sqrt{x\times x}

=6\times x

\sqrt{36x^2}=6x

Therefore the simplified radical form is  \sqrt{36x^2}=6x

2)Given expression is \sqrt{72x^3}

To find the simplified radical form of the given expression :

\sqrt{72x^3}

=\sqrt{72\times x^3}

=\sqrt{72}\times \sqrt{x^3}

=\sqrt{9\times 8}\times \sqrt{x\times x\times x}

=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}

=3\times 2\sqrt{2}\times x\sqrt{x}

\sqrt{72x^3}=6x\sqrt{2x}

Therefore the simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) Given expression is \sqrt{15x^8}

To find the simplified radical form of the given expression :

\sqrt{15x^8}

=\sqrt{15\times x^8}

=\sqrt{15}\times \sqrt{x^8}

=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}

=\sqrt{15}\times x^4

\sqrt{15x^8}=\sqrt{15}x^4

Therefore the simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) Given expression is \sqrt{36x^7}

To find the simplified radical form of the given expression :

\sqrt{36x^7}

=\sqrt{36\times x^7}

=\sqrt{36}\times \sqrt{x^7}

=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}

=6\times x^3\sqrt{x}

\sqrt{36x^7}=6x^3\sqrt{x}

Therefore the simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

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