To find the absolute value of a negative number, you can simply remove the negative. ., -235 turns into 235, and 235 is greater than 220.
Answer:
f(x) = x(x +4)(x -3)
Step-by-step explanation:
Zeros at -4, 0, and 3 tell you the factorization is ...
f(x) = a(x +4)(x)(x -3)
Then f(2) = a(6)(2)(-1) = -12a.
The graph shows f(2) = -12, so a=1. That makes the function rule:
f(x) = x(x +4)(x -3)
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If you want it multiplied out, it will be
f(x) = x^3 +x^2 -12x
Answer:
6+7= 13
Step-by-step explanation:
you replace a with 7
If an expression has an equal to sign, it is called an equation.
If it has less than or greater than sign, then it is called inequality.
It is also an inequality if it has greater than or equal to or less than or equal to signs. ( ≥, ≤)
The sum of 1 & x is x+1
This sum is less than 5
So we have
x + 1 < 5
Now y minus 2 means
y - 2
Now it says 3 is less than (y-2)
So we get
3 < y - 2
1)
the sum of 1 and x is less than 5 => x + 1 < 5
2)
3 is less than y minus 2 => 3 < y - 2
We can figure this out using what's called an explicit formula.
![f(n)=f(1)+d(n-1)](https://tex.z-dn.net/?f=f%28n%29%3Df%281%29%2Bd%28n-1%29)
n is the term we are looking for.
f(1) is the first term of the sequence, which in this case, is 100.
d is the common difference, which in this case, is -8.
f(n) = 100 - 8(n - 1)
f(n) = 100 - 8n + 8
f(n) = 108 - 8n
Now, we can input 50 for n and solve.
f(50) = 108 - 8(50)
f(50) = 108 - 400
f(50) = -292
The 50th term in this sequence is -292.