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Vedmedyk [2.9K]
3 years ago
11

In parallelogram ABCD , AE=x2−8 and CE=2x .

Mathematics
2 answers:
Anna71 [15]3 years ago
6 0

Answer:

16

Step-by-step explanation:


QveST [7]3 years ago
3 0
Answer: 8

The point E in the parallelogram is located at the crossing point of the diagonal line. It can be concluded that the distance of AE is equal to CE, or equal to 1/2 AC. Then you can get three equation like this:
AE=CE
<span>AE=x^2−8
CE=2x .

Using these equation you can find the value of x
AE= CE
</span>x^2−8 = 2x
x^2−2x-8 = 0
(x- 4)     (x+2)
x1= 4     x2= -2

Excluding the minus result, you can get that AE= CE= 4
Then AC would be: 
AC= AE+CE
AC= 4 + 4= 8
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Answer:

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3 years ago
In the parallelogram below, solve for Y<br> Options <br> 4<br> 10<br> 25<br> 100
Lapatulllka [165]

Answer:

x = 4

y = 4

Step-by-step explanation:

the front triangle has two 40° angles (sum of all ∡'s must be 180°)

the unlabeled lower-left angle then is 40°; this angle corresponds to the angle in the other triangle labeled as 10y°

therefore, 10y = 40 so y = 4

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6 0
3 years ago
Please show work it’s for calc
VashaNatasha [74]

Answer:

-93

Step-by-step explanation:

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3 0
3 years ago
Need help please! Can someone explain?
Lynna [10]

A=(3.14)r^2

A=(3.14)3^2

A=(3.14)9

A=28.26ft^2

Hope it helps and is correct :)

3 0
3 years ago
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