Answer:
The time taken for the projectile to reach the given height is 1.2 s.
Step-by-step explanation:
Given;
height of travel, h = 25 ft
initial velocity of the projectile, u = 15 ft/s
The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;
h = ut + ¹/₂gt²
25 = 15t + ¹/₂(9.8)t²
25 = 15t + 4.9t²
4.9t² + 15t - 25 = 0
solving the quadratic equation, we will have the following solution of t;
t = 1.2 s
Therefore, the time taken for the projectile to reach the given height is 1.2 s.
Answer:
pretty sure the answer is the last one
Step-by-step explanation:
you put them to the 4th power to get rid of the root sign
Im not really sure
But hope I still get it
Step-by-step explanation:
If np is attitude
5x^2+10=90
5x^2=80
x^2=16
X=+-4
angle npo=90 degeees
