Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
Answer:
c = 2
d = 28
Step-by-step explanation:
Please see the attached file for explanation
The lesser of the numbers given are -16 because -16 is more negative.
Answer:
48 degrees
Step-by-step explanation:
inscribed angle is always equal to the measure of the arc
We know that these two angles are equal to each other (There is the "congruent" sign) so we can set them equal to each other and solve for x
3x - 17 = 25 - 3x
(3x + 3x) - 17 = 25 + (-3x + 3x)
6x + (- 17 + 17) = 25 + 17
6x/6 = 42/6
x = 7
Hope this helped!
