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cricket20 [7]
3 years ago
7

Factor the Difference of Square. 25x2 _ 16

Mathematics
2 answers:
Alenkinab [10]3 years ago
5 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

Oliga [24]3 years ago
4 0

Answer:

x = {-0.8, 0.8}

Step-by-step explanation:

Simplifying

25x2 = 16

Solving

25x2 = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '25'.

x2 = 0.64

Simplifying

x2 = 0.64

Take the square root of each side:

x = {-0.8, 0.8}

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Step-by-step explanation:

300 meters/4 mps = 75 seconds

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How to calculate geometric mean
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2 years ago
Can you help me please, please answer seriously, no links please​
Talja [164]

Answer:

Centre: (\frac{1}{2} ,2)

Radius = 2

Step-by-step explanation:

General formula for a circle: (x-a)^2+(y-b)^2=r^2, where r= the radius of the circle and (a,b) is the centre of the circle.

To find the centre and radius of the circle we should re-write the given equation in the form of the general formula.

So, put the terms with the same variables together:

4x^2-4x+4y^2+16y+1=0

We can see that there is a common factor of 4, so let's simplify by dividing by 4:

x^2-x+y^2+4y+\frac{1}{4} =0

Here we can get it into the general formula by completing the square.

We do this by turning a quadratic with form ax^2+bx+c=0 into the form (x-d)^2-e+c=0, where d is half of the coefficient of x, e is d^2 and c is the constant of the quadratic.

So let's re-write the equation of the circle:

(x-\frac{1}{2} )^2-\frac{1}{4} +(y-2)^2-4+\frac{1}{4} =0

Simplify: (x-\frac{1}{2} )^2 +(y-2)^2-4} =0

Now we can see that it's very similar to the general equation and all we have to do is bring the 4 over to the right side.

(x-\frac{1}{2} )^2 +(y-2)^2} =4

So, now we can find the radius and centre.

(a,b) = (\frac{1}{2} ,2)

r^2=4, r=2

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3 years ago
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sergij07 [2.7K]
The answer should be D. I hope this helps and could I get brainliest please?!
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