![(8a^{-3})^\frac{2}{3}=(8 \cdot \frac{1}{a^3})^\frac{2}{3}=(\frac{8}{a^3})^\frac{2}{3}=\sqrt[3]{(\frac{8}{a^3})^2}=\sqrt[3]{\frac{64}{a^6}}=\frac{\sqrt[3]{64}}{\sqrt[3]{a^6}}=\frac{4}{a^2}](https://tex.z-dn.net/?f=%288a%5E%7B-3%7D%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%288%20%5Ccdot%20%5Cfrac%7B1%7D%7Ba%5E3%7D%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%28%5Cfrac%7B8%7D%7Ba%5E3%7D%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B8%7D%7Ba%5E3%7D%29%5E2%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B64%7D%7Ba%5E6%7D%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B64%7D%7D%7B%5Csqrt%5B3%5D%7Ba%5E6%7D%7D%3D%5Cfrac%7B4%7D%7Ba%5E2%7D)
It doesn't equal any of the answers A, B, C.
The answer is D.
Answer:
Se calcula el maximo comun divisor.
195/5 = 39
275/5 =55
315/5 =63
460/5= 92
525/5 =105
Se deben utilizar 354 garrafas
Step-by-step explanation:
Descomponemos cada número en factores primos.
Después, señalamos los factores comunes.
A continuación, en cada uno de los comunes, escogemos el factor con menor exponente.
Y por ultimo, multiplicamos los factores elegidos.
195 3 275 5 315 3 460 2 525 3
65 5 55 5 105 3 230 2 175 5
13 13 11 11 35 5 115 5 35 5
1 1 7 7 23 23 7 7
1 1 1
I’m pretty sure you just use pythag for that so 1.5^2 + h^2 = 2.5^2 and once you solve that you should have your answer and don’t forget to root it after
Three hundred and ten million, seven hundred sixty-three thousand, one hundred and thirty-six
You need to use basic algebra for this.
For this I’ll use o as the items and p for the payment. First you need to find out how long it took for all the items to scan, so if it took each item 2 seconds to be scanned you need to times the total number of items (o) by two e.g. o x 2 = 62 items times two seconds which is equivalent to 62 seconds (1.02 minutes) after this step you need to minus the total time it took to scan the items for the transaction time (2 minutes) e.g. 2.00 - 1.02 = 2.58 minutes.
Hope this helped :)
