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2 years ago

Find The slope of the line that passes through the point (2,4) ,(3,8)

Mathematics

1 answer:

zlopas [31]2 years ago

5 0

The slope should be m=4.

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What is the domain of -7,1

PSYCHO15rus [73]

Answer:

Domain? Do you by chance mean quadrant? If so it's the 3rd quadrant.

Step-by-step explanation:

In the future try to imagine quadrant 1 in the top right and then going counter-clockwise! It'll help!

6 0

2 years ago

Enter the number that belongs in the green box.

ale4655 [162]

Answer:

the green box is 0

Step-by-step explanation:

we are asked to find the <u>x-intercept</u>, which means y = 0

(x, y)

Another way to test this is plug it in 1 for x! (1, y) where x = 1

$y = \frac{2x^{2} -3x+1}{2x^{2} +8x+6} \\\\$

$y = \frac{2(1)^{2} -3(1)+1}{2(1)^{2} +8(1)+6}$

$y = \frac{2(1) -3(1)+1}{2(1) +8+6}$

$y = \frac{2 - 3 + 1}{2 + 8 + 6}$

$y = \frac{-1+1}{10 + 6}$

$y = \frac{0}{16}$

y = 0

6 0

1 year ago

Find the value of w,then x. Round to the nearest tenth

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

12 / tan 42 = 13.32......

12 / sin 27 = 26.43....

26.43² - 12² = 552.24....

square root of 552.24... = 23.5

23.5 - 13.3 = 10.2

7 0

2 years ago

In one U.S city, the taxi cost is $2 plus $0.60 per mile. If you are traveling from the airport, there is an additional charge o

anzhelika [568]

Answer:

60 miles

Step-by-step explanation:

Let

x ----> the number of miles

we know that

The number of miles multiplied by $0.60 per mile plus $2 plus the charge of $5.50 for tolls (because you are travelling from the airport) must be equal to $43.50

The linear equation that represent this problem is

$0.60x+2+5.50=43.50$

Solve for x

Combine like terms left side

$0.60x+7.50=43.50$

subtract 7.50 both sides

$0.60x=43.50-7.50$

$0.60x=36$

divide by 0.60 both sides

$x=60\ miles$

5 0

2 years ago

1. find the equation of the circle with center at (-3,1) and through the point (2,13)

daser333 [38]

Try this solution:
Common view of the equation of the circle is (x-a)²+(y-b)²=r², where point (a;b) is centre of the circle, r - radius.
1. using the coordinates of the centre and point (2;13) it is possible to define the radius of the circle: r=√(5²+12²)=13;
the equation is (x+3)²+(y-1)²=13² or (x+3)²+(y-1)²=169;
2. using the coordinates of the centre and the radius: (x-2)²+(y-4)²=6² or (x-2)²+(y-4)²=36.

7 0

2 years ago