2 × (x + 3) < 5
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You will have to use trial and error in order to find the values for x and y.
Just keep plugging values until you get 7.
I found x is equal to 2 and y is equal to 5.
3(2) + (1/5)5 = 7
6 + 5/5 = 7
6 + 1 = 7
7 = 7
Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
A=B maybe ...
what is that symbols of a and b
