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2 years ago

Can anyone help me please?

1 answer:

6 0

Help with what? I am not sure what other question you asked that you need help on. What is the question?

You might be interested in

Setler79 [48]

Answer:

x=19/4 , y=3/4

Step-by-step explanation:

7 0

3 years ago

Scilla [17]

I hope this helps you

4 0

2 years ago

lutik1710 [3]

Circumference = Diameter * $\pi$

So 9 $\pi$ is the answer

3 0

2 years ago

zepelin [54]

8a^2 + 3a^2

11a^2

since both have a^2 you only have to add the coefficients

5 0

2 years ago

gavmur [86]

Solution:

we are given that

If G is the midpoint of FH, it mean that

$FG=GH$

we are also given that

$FG=11x-7 ,GH= 3x+9$

So we can write

$11x-7=3x+9\\
\\
11x-3x=7+9\\
\\
8x=16\\
\\
x=2$

So $FG=11x-7=11*\frac{1}{2}-7=11*2-7=15$

3 0

3 years ago