72:64 = 9 ____ quantitties

He logical statement represents the inverse of the conditional statement “if you are human, then you were born on earth.”

Artyom0805 [142]

The conditional statement “if you are human, then you were born on earth.”

The logical statement is the inverse of the conditional statement.

So, the logical statement is If you are born on earth then you are a human.

Now we can say that our conditional statement is absolutely true in all condition

which states If i am a human⇒ I am born on earth

but logical statement is not true because If i am born on earth it does not mean that i can be only human, i can be other creature also.

The answer can be depicted by venn diagram also.

8 0

3 years ago

a rabbit can run 35 miles per hour. a fox run can run 21 miles in half an hour.which animal is faster,and by how much

lord [1]

Answer:

the rabbit by 14 miles per hour

Step-by-step explanation:

The rabbit because if you subtract 35 from 21 it gives you 14

6 0

3 years ago

Read 2 more answers

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

3 years ago

If the rat moves through the maze randomly, out of 100 attempts, how many times would you expect Romeo to end up in room A? How

yuradex [85]

50 and 50 because half of 100 is 50 and 50

3 0

3 years ago

Make t as the subject!! HELP MEE

Umnica [9.8K]

Answer:

t = (p^2/mn) - 1/n

Step-by-step explanation:

Here, we want to make t the subject of the formula

we start by equating both sides so as to remove the root

we have this as;

m(t + n)/t = p^2

m(t + n) = tp^2

mt + mn = tp^2

mn = tp^2 - mt

mn = t(p^2-m)

t = (p^2 - m)/mn

t = p^2/mn - 1/n

6 0

3 years ago