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3 years ago

45 was divided by a power of ten to get 4.5. What power of ten was it divided by?

Mathematics

2 answers:

vekshin13 years ago

7 0

45 was divided by 10

Nonamiya [84]3 years ago

5 0

thw power of ten that it was divided by was 10

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Use the ratio table to solve the percent problem.

aliina [53]

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= 90 * 0.20
= 18

In short, Your Answer would be 18

Hope this helps!

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3 years ago

Round 257,650 to the nearest hundred

allochka39001 [22]

The answer is either 257,600 or 257,700. I think you need to round up to 127,700.

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3 years ago

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Find the value of a in the equation <br> 5/a + 3 = 3/a - 2

Nitella [24]

The correct answer is a =9.5

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3 years ago

You are trying to determine if you should accept a shipment of eggs for a local grocery store. About 4% of all cartons which are

padilas [110]

Answer:

0.8809

Step-by-step explanation:

Given that:

The population proportion p = 4% = 4/100 = 0.04

Sample mean x = 16

The sample size n = 300

The sample proportion $\hat p =\dfrac{x}{n}$

= 16/300

= 0.0533

∴

$P(\hat p \leq 0.0533) = P\bigg ( \dfrac{\hat p - p}{\sqrt{\dfrac{P(1-P)}{n}}}\leq\dfrac{0.0533 - 0.04}{\sqrt{\dfrac{0.04(1-0.04)}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.04(0.96)}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.0384}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{1.28 \times 10^{-4}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{0.0113}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq1.18}\bigg )$

From the z tables;

= 0.8809

Let X be the random variation that follows a normal distribution;

Then;

population mean $\mu$ = n × p

population mean $\mu$ = 300 × 0.04

population mean $\mu$ = 12

The standard deviation $\sigma = \sqrt{np(1-p)}$

The standard deviation $\sigma = \sqrt{300 \times 0.04(1-0.04)}$

The standard deviation $\sigma = \sqrt{11.52}$

The standard deviation $\sigma = 3.39$

The z -score can be computed as:

$z = \dfrac{x - \mu}{\sigma}$

$z = \dfrac{16 -12}{3.39}$

$z = \dfrac{4}{3.39}$

z = 1.18

The required probability is:

P(X ≤ 10) = Pr (z ≤ 1.18)

= 0.8809

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3 years ago

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MArishka [77]

Answer:

the answer is decreases

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