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gogolik [260]
3 years ago
5

7g:1kg to its simplest form​

Mathematics
1 answer:
hammer [34]3 years ago
5 0

Answer:

7kg:1kg=7:1 itself

Because 7 and 1 has one '1' as a common factor, so they can't be simplified

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Find dy/dx by implicit differentiation for x + 2y = xy.
Stella [2.4K]
Ok to find dy/dx of x+2y=xy we take derivative of both sides with respect to x

1+2dy/dx = x*dy/dx +y*dx/dx
1+ 2dy/dx = x*dy/dx + y* 1
2dy/dx +1 = x*dy/dx + y

2y’ + 1 = xy’ + y

2y’ + 1 - xy’ = y

2y’ -xy’ = y - 1

y’(2-x) = y - 1

so we get finally

y’= (y-1)/(2-x)

Hope this helps you understand the concept! Any questions please ask! Thank you so much!!
4 0
3 years ago
A) If it takes 125 chinchillas to make a coat and he needs to make 10 coats, how many chinchillas must Barton have by the end of
IrinaK [193]
A) 125 * 10 = 1250 chinchillas in a year;
1250 * 2 = 2500 chinchillas in two years;

b) y = x + 433, where 433 = 933 - 500;

c) 933 + 433 = 1366 chinchillas they have <span>at the end of two years;</span>
7 0
3 years ago
The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
Read 2 more answers
Translate this sentence into an equation.
kakasveta [241]

Answer:

21+j=55

Step-by-step explanation:

It says sum, which means to add(+). So you add 21 and j (21+j) and that equals 55 (=55). Then you add all the pieces together and you get 21+j=55

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=2%28%203x%20%2B%201%29%20%3D%2011" id="TexFormula1" title="2( 3x + 1) = 11" alt="2( 3x + 1) =
lisabon 2012 [21]

I'm assuming you need to evaluate/simplify the equation, so you need to isolate/get x by itself in the equation:

2(3x + 1) = 11        Divide by 2 on both sides

3x + 1 = \frac{11}{2}        [11/2 or 5.5] Subtract by 1 on both sides

3x=\frac{11}{2}-\frac{2}{2}            [make the denominator the same to combine fractions]

3x = \frac{9}{2}        Divide by 3 on both sides

x = \frac{9}{6}=\frac{3}{2}  

7 0
2 years ago
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