$\alpha \div 6 + 4= 16\\\\Subtract ~4~on~both~sides\\\\ \alpha \div 6 +4 -4 = 16 -4\\\\ \alpha \div 6 = 16 - 4\\\\ \alpha \div 6 = 12\\\\Multiply~both~sides~by~6\\\\a \div 6\times 6 = 12\times 6\\\\ \alpha = 12\times 6 \\\\ \boxed{\bf{\alpha = 72}}$

Your final answer is alpha = 72.

5 0

3 years ago

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How can we factorise the expression: 2x^6+17x^3+8?

LekaFEV [45]

Answer:

$(a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1)$

Step-by-step explanation:

$2x^6+17x^3+8 \\ = 2x^6+16x^3 + {x}^{3} +8 \\ = 2{x}^{3} ( {x}^{3} + 8) + 1( {x}^{3} + 8) \\ = ( {x}^{3} + 8)(2 {x}^{ 3} + 1) \\ = ( {x}^{3} + {2}^{3} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + {2}^{2} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1) \\$

7 0

3 years ago

7g:1kg to its simplest form​

7g:1kg to its simplest form