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gayaneshka [121]
3 years ago
12

G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.

Mathematics
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

  7

Step-by-step explanation:

The two angles of interest are either side of angle bisector EG, so are congruent.

  3n -1 = 20

  3n = 21 . . . . . add 1

  n = 7 . . . . . . . divide by 3

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(12x + y + z = 26
mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}26\\17\\23\end{array}\right].

Step 3:

The linear system B is represented as

\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}23\\17\\26\end{array}\right].

Step 4:

The linear system C is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\11\\12\end{array}\right].

Step 5:

The linear system D is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}12\\11\\4\end{array}\right].

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0
3 years ago
Math Help!!! How many x-intercepts does the graph of the function have?
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<span>if it hits it more than once, it is NOT a function. 
</span>
An example is a polynomial function to the infinite degree. That is 
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6 0
3 years ago
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Answer:

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Step-by-step explanation:

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