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NARA [144]
3 years ago
14

Researchers have found a strong connection between the amount of athletes foot powder

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0
What question are you asking?

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The diagram shows a cuboid.<br> 4 cm<br> 5 cm<br> 9 cm<br> What is the surface area of the cuboid?
katrin2010 [14]

Answer:

202 cm^2

Step-by-step explanation:

SA = 2LW + 2LH + 2WH

SA = 2(4 cm)(5 cm) + 2(4 cm)(9 cm) + 2(5 cm)(9 cm)

SA = 40 cm^2 + 72 cm^2 + 90 cm^2

SA = 202 cm^2

6 0
2 years ago
At the sewing store, Eva bought a bag of mixed buttons. She got 64 large buttons and 16 small buttons. What percentage of the bu
DIA [1.3K]

Answer:

80% of the buttons were large.

Step-by-step explanation:

Recall that percentages are fractions.

We first need to find the total number of buttons that Eva bought

64 + 16 = 80

Then we need to divide 64 into 80 as a fraction of the whole (80 is our whole)

64 ÷ 80 = 0.8

To convert our decimal to a percentage, we must multiply it by 100.

0.8 * 100% = 80%

Therefore, 80% of the buttons were large.

7 0
3 years ago
Which table shows values for the function y=2(1/2)^x
Talja [164]
<span>y=2(1/2)^x
</span>
x = 0; <span>y=2(1/2)^0 = 2(1) = 2
x = 1; </span><span>y=2(1/2)^1 = 2(1/2) = 1

answer is the last one.</span>
6 0
3 years ago
Josh is solving the equation 2 % + 2% and predicts that his
gregori [183]
4 5/6 Hope this helps.

You have to find the common denominator for 1/3 & 4/8. & it’s 24. By doing that you have to multiply 3x8, when you do that you also have to multiply 1x 8 so you get 8/24 , same with 4/8 but with three so you get 12/24. Then add your answer 20/24, which equals out to 20/24 which reduces to 5/6. Add 5/6 to 2+2 and you’re left with 4 5/6. Hope this helps.
4 0
3 years ago
Find the value of x.
nikklg [1K]

Answer:

x = 13

Step-by-step explanation:

Sum or interior angles of a triangle is 180,

6x + 19 + 5x - 15 + 3x - 6 = 180

6x + 5x + 3x + 19 - 15 - 6 = 180

14x + 19 - 21 = 180

14x - 2 = 180

14x = 180 + 2

14x = 182

x = 182 / 14

x = 13

5 0
2 years ago
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