Step-by-step explanation:
Use SOH-CAH-TOA.
Sine = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tangent = Opposite / Adjacent
You're given an angle, the adjacent side to that angle, and the hypotenuse. So use cosine.
Cosine = Adjacent / Hypotenuse
cos 37° = 48 / x
Multiply both sides by x.
x cos 37° = 48
Divide both sides by cos 37°.
x = 48 / cos 37°
If desired, use a calculator to evaluate.
x ≈ 60.1
Answer:
10.9361
Step-by-step explanation:
The lower control limit for xbar chart is
xdoublebar-A2(Rbar)
We are given that A2=0.308.
xdoublebar=sumxbar/k
Rbar=sumR/k
xbar R
5.8 0.42
6.1 0.38
16.02 0.08
15.95 0.15
16.12 0.42
6.18 0.23
5.87 0.36
16.2 0.4
Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8
Xdoublebar=88.24/8
Xdoublebar=11.03
Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8
Rbar=2.44/8
Rbar=0.305
The lower control limit for the x-bar chart is
LCL=xdoublebar-A2(Rbar)
LCL=11.03-0.308*0.305
LCL=11.03-0.0939
LCL=10.9361
Answer:
x = 6
Step-by-step explanation:
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is
x² + (x + 2)² = 10² ← expand parenthesis on left side and simplify
x² + x² + 4x + 4 = 100 ( subtract 100 from both sides )
2x² + 4x - 96 = 0 ( divide through by 2 )
x² + 2x - 48 = 0
(x + 8)(x - 6) = 0 ← in factored form
equate each factor to zero and solve for x
x + 8 = 0 ⇒ x = - 8
x - 6 = 0 ⇒ x = 6
however, x > 0 , then x = 6
Answer:
20 oatmeal cookies
Step-by-step explanation:
4/5 of 25 is 20
If you are working on proportions, you can do 4/5=x/25
Answer:
1. |y| sqrt(10)
2. |x| sqrt(x)
3. a^2 sqrt(a)
4. 4 |y|^3 sqrt(3)
5. 1/4 *|x| sqrt(3x)
Step-by-step explanation:
1. sqrt(10y^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(y^2) sqrt(10)
|y| sqrt(10)
We take the absolute value of y because -y*-y = y^2 and the principle square root is y
2. sqrt(x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(x)
|x| sqrt(x)
3. sqrt(a^5)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(a^4) sqrt(a)
a^2 sqrt(a)
4. sqrt(16 y^7)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(16) sqrt(y^6)sqrt(y)
4 |y|^3 sqrt(3)
5. sqrt(3/16x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(1/16) sqrt(x^2)sqrt(3x)
1/4 *|x| sqrt(3x)
