If $1,000 is invested in an account that pays 5% interest compound annually, an expression that represents the amount in the acc
2 answers:
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Here's the solution,
volume of cylinder :
=》
where,
- r = radius
- h = height
now, let's solve
=》
=》
So, volume = 2000.2 cm³
<h3>Answer: 33%</h3>
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Explanation:
1/3 converts to the decimal form 0.333333... where the 3's go on forever
5/3 is a similar story but 5/3 = 1.666666.... where the '6's go on forever
The notation indicates that the 6's go on forever.
So,
The horizontal bar tells us which digits repeat. As another example,
The three dots just mean "keep this pattern going forever".
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Everything mentioned so far has the decimal portions go on forever repeating some pattern over and over.
The only one that doesn't do this is 33% which converts to the decimal form 0.33
The value 0.33 is considered a terminating decimal since "terminate" means "stop". So this is the value that doesn't fit in with the other three items mentioned.
Answer:
The value of the test statistic is z = 1.39.
The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.
Step-by-step explanation:
Using traditional methods it takes 92 hours to receive an advanced flying license.
This means that at the null hypothesis, it is tested if the mean is of 92, that is:
Test if there is evidence that the technique lengthens the training time
At the alternative hypothesis, it is tested if the mean is more than 92, that is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
92 is tested at the null hypothesis:
This means that
A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.
This means that
Value of the test statistic:
The value of the test statistic is z = 1.39.
P-value of the test and decision:
The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.
Looking at the z-table, z = 1.39 has a p-value of 0.9177.
1 - 0.9177 = 0.0823.
The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.