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Kryger [21]
3 years ago
9

An English professor determined the mean of her final exam scores to be 78 with a standard deviation of 6.3. Find the minimum an

d maximum “usual” values of the test scores.
65.4 and 90.6


69.7 and 86.3


71.7 and 84.3


59.1 and 96.9
Mathematics
3 answers:
Morgarella [4.7K]3 years ago
5 0

Solution: We are given:

Mean =78, Standard-deviation =6.3

We know that a usual values of the test scores falls within 2 standard deviation from the mean.

Therefore, the minimum usual test score is:

Mean - 2 Standard-deviation

78-2 \times 6.3

78-12.6

65.4

The maximum usual test score is:

Mean + 2 Standard-deviation

78+2 \times 6.3

78+12.6

90.6

Therefore, the minimum and maximum “usual” values of the test scores are:

65.4 and 90.6

dem82 [27]3 years ago
5 0
<h2>Answer:</h2>

The minimum and maximum usual value of the test scores are:

              65.4 and 90.6

<h2>Step-by-step explanation:</h2>

We know that:

The maximum usual value is two standard deviations above the mean and the minimum usual value is two standard deviation below the mean.

i.e.

Maximum value= Mean+2×standard deviation.

i.e.   Maximum value= 78+2×6.3

Maximum value= 90.6

and

Minimum value= Mean-2×standard deviation.

Minimum value= 78-2×6.3

i.e. Minimum value= 65.4

Mikayla Carter3 years ago
0 0

69.7 and 86.3

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