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iogann1982 [59]
4 years ago
15

Simplifying inside parentheses first pt. 2

Mathematics
1 answer:
Brut [27]4 years ago
5 0

Answer:

The answer to your question is the second option

Step-by-step explanation:

Process

Simplify using exponents laws, first inside the parentheses and then outside the parentheses.

                             [\frac{a^{-2}b^{2}}{a^{2}b^{-1}} ]^{-3}

a) Simplify a

                        a⁻² a⁻² = a⁻⁴

b) Simplify b

                        b² b¹ = b³

c) Write the result

                        [\frac{b^{3}}{a^{4}}]^{-3}

d)                      [\frac{a^{4}}{b^{3}}]^{3}

e) Simplify

                       \frac{(a^{4})^{3}}{(b^{3})3}

f) Result

                      \frac{a^{12}}{b^{9}}

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Answer:

Area = 16sq inches

Perimeter =  16 inches

Step-by-step explanation:

The shape of body is a square:

 Area = S²

 Perimeter = 4S

S is the side length

So;

      S  = 4inches

Therefore;

       Area = S²   = 4²   = 16sq inches

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7 0
3 years ago
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ArbitrLikvidat [17]

If you mean 27^{\frac{1}{3}}, then the answer is 3.

In fact, rational exponents work like this:

a^{\frac{b}{c}}=\sqrt[c]{a^b}

So, in your case,

27^{\frac{1}{3}}=\sqrt[3]{27} = 3

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The 2th term of The A.P is 7 and 4th term is 28 Find The Common difference and The first term.
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Answer:

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Step-by-step explanation:

The n th term of an AP is

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Given a₂ = 7 and a₄ = 28 , then

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Subtract (1) from (2) term by term to eliminate a₁

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d = 10.5 ← common difference

Substitute d = 10.5 into (1)

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6 a)
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