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jek_recluse [69]
2 years ago
11

Ayden has 6 red rubber ducks, 4 blue rubber ducks, 8 green rubber ducks, and 2 yellow rubber ducks at home. He will randomly sel

ect two ducks to take to school (for some reason) without replacement. What is the probability that Ayden will select a blue rubber duck, and then a green rubber duck.
Mathematics
1 answer:
Oliga [24]2 years ago
3 0

Answer:

percentage he will select the blue rubber duck over the green ruber duck is (blue duck 1.25) (green duck 0.25)

Step-by-step explanation:

your person without a brain

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maxine hosted a dinner party at her favorite restaurant. she had to pay $12 per guest. the restaurant took $72 off the bill due
kolbaska11 [484]
" $300 = $12g - $72 " .
4 0
3 years ago
Which one goes first a negative or a positive
Zielflug [23.3K]

no number can have a positive and a negative at the same time. a negative number has a negative sign and a positive number has a plus sign.

6 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
PLEASE HELP
postnew [5]

Answer:

Below

Step-by-step explanation:

Substituting the given values:

f(6) = 6(2/3) - 2 =   cube root of 6^2 - 2 = cube root 36 - 2

f(-6)=  (-6)(2/3) - 2 =   cube root of(-6)^2 - 2 = cube root 36 - 2

So This is true,

f(6) =   cube root of 6^2 - 2 = cube root 36 - 2 = 1.3019

2 * f(3) = 2 *  (cube root of 3^2 - 2 )  =  2 * (cube root of 9 - 2) = 0.1602

So False,

4 0
3 years ago
Help
kykrilka [37]

Let n =  the hours elapsed when the two trains are 660 miles apart.


Let the first train travel east and the second train travel west.

The distance traveled by the first train is

x = (50 mi/h)*(n h) = 50n mi


The distance traveled by the second train is

y = (60 mi/h)*(n h) = 60n h


The distance between the two trains after n hours is

x + y = 50 n + 60n = 110n mi


Because this distance is 660 miles, therefore

110n = 660

n = 6 hours


Answer: 6 hours


I hope this helps. Sorry it took so long

3 0
3 years ago
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