PLEASE HELP!! Explain your answer!

1 answer:

5 0

eg. x is the number of milk chocolate candy bars, y is the number of white chocolate of candy bar

x + y = 330
2x + 3y = 900

From first equation
x + y = 330
x = 330 - y

From second equation, subtitute x with 330 - y
2x + 3y = 900
2(330-y) + 3y = 900
660 - 2y + 3y = 900
660 + y = 900
y = 900-660
y = 240

The number of white chocolate candy bars is 240

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Shankar is teaching 2 courses, let us call them 435 and FYS. 435 has 3 sophomores, 8 juniors and 13 seniors; FYS has 5 sophomore

Mice21 [21]

Answer:

The probability that both students are of the same type is $\frac{149}{432}$ .

Step-by-step explanation:

The students in 435 are: {3 sophomores, 8 juniors and 13 seniors}

Number of students in 435 = 3 + 8 + 13 = 24

The students in FYS are: {5 sophomores, 7 juniors and 6 seniors}.

Number of students in FYS = 5 + 7 + 6 = 18

The teacher picks 1 student from each class.

The probability that both students are of the same type is:

P (Same type students) = P (Both are Sophomores) + P (Both are Juniors)

+ P (Both are Seniors)

= P (Sophomore ∩ Course 435) × P (Sophomore ∩ Course FYS)

+ P (Junior ∩ Course 435) × P (Junior ∩ Course FYS)

+ P (Senior ∩ Course 435) × P (Senior ∩ Course FYS)

$=[(\frac{3}{24} )\times(\frac{5}{18})]+[(\frac{8}{24} )\times(\frac{7}{18})]+[(\frac{13}{24} )\times(\frac{6}{18})]\\=\frac{15+56+78}{432}\\ =\frac{149}{432}$