A sample word problem to calculate the volume and surface area of a three-dimensional object would be: "A logistics company has a wide area that is 300m^2 and has a parking space that is 50m in height and is 12 feet long. Find the volume of the parking space"
<h3>What is a Word Problem?</h3>
This refers to the use of words that describes a real scenario that would lead to a mathematical calculation.
Hence, to make a sample word problem based on the given description, the above description should be helpful, and remember that 
is 3.142 when doing your calculations.
Read more about word problems here:
brainly.com/question/13818690
#SPJ1
Windows stores information from the Credential Manager application in secure folders called<u> VAULTS.</u>
<u></u>
Explanation:
- A credential vault is a database used to store passwords and similar cryptographic key material.
- The most common data stored in a credential vault are current and historical passwords to privileged accounts.
- All credentials are saved in special folders on the computer, a place called Vaults. Moreover, you can back up all credentials to a file and restore them on to different computer.
- Vault is a shareware program that acts as a bank vault, or safe, where you can keep you private information or files hidden and secure.
- Everything in the vault is protected with an advanced encryption, and requires a password (your password) to open the vault to access the information.
C- A graphic designer is the awnser
Answer: C. Differential backup
Explanation: There are several ways od ensuring the preservation and storage of data even cases of disaster, one of such ways is data data mirroring which allows data to be replicated or copied in real time and several backup options. In cases where there there is need to restore a server, the warm recovery site provides a data or disaster recovery option used to mitigate the effect of data loss on organization. In the absence of data mirroring, differential backup option, provides the quickest recovery option as it only requires changes in the data stored after the last full backup. These speed experieced should be expected due to the relatively low data been dealt with rather than the entire data.
