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3 years ago

Simplify the expression (1/5k)^2

Mathematics

1 answer:

sesenic [268]3 years ago

6 0

Answer:

k^2 ÷ 5^2

Step-by-step explanation:

— <<Simplify

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What is the common factors of 12 and 42 also 63 and 84

kaheart [24]

$12|2 \\ 6 \ |2 \\ 3 \ |3 \\ 1 \\\\12=2^2*3 \\\\ 42|2\\21|3\\7\ |7\\1 \\\\42=2*3*7 \\\\ G.C.F(12;42)=2*3=6 \\\\\\\ 63|3 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 63=3^2*7 \\\\ 84|2 \\ 42|2 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 84=2^2*3*7 \\\\ G.C.F(63;84)=3*7=21$

3 0

3 years ago

Find the interquartile range for the box plot below.*

alexgriva [62]

Answer:

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Step-by-step explanation:

u should do those step and i think u will find the answer

6 0

3 years ago

The area of a compact disc is 78.53 square centimeters. What is the radius of the disc? Use pi = 3.14

Tom [10]

Answer:

r = 5 cm

Step-by-step explanation:

A = πr²

78.53 = (3.14)r²

divide by 3.14

25 = r²

r = ±5

r = 5

5 0

3 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

3 years ago

A recipe needs 23 cup(s) of sugar for every 212 cups of flour. If you plan to use 10 cups of flour, how much sugar will you need

arlik [135]

Answer: you will need approximately 23 grams

Step-by-step explanation: but thats approximately

4 0

3 years ago