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kipiarov [429]
3 years ago
6

Whats the value of tan 11π/6?

Mathematics
1 answer:
Illusion [34]3 years ago
4 0
The exact solution of <span>tan 11π/6</span><span> is as follows:

First change the angle into degrees.

11(</span>π/6) (180°/π) = 330°

Then we calculate the tangent of the angle above and it as follows:

tan 330° = (√3)/2

Hope this answers the question. Have a nice day.
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Which ordered pair is a solution of the equation 2x-3y=19
goldenfox [79]
D because 5 times 2 is 10 and - cuts off - so -3 times -3 would be 9 so 10+9 is 19 :)
7 0
3 years ago
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Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w
siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$  is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4} $

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0
3 years ago
HELP PLZZZZZZZZZZZZ!!!!!!!!!!!!!!!! <br> ILL GIVE YOU 15 POINTS
seropon [69]

Answer:

B

Step-by-step explanation:

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so for A

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so A is wrong

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and \sqrt{16/9} Is 4/3 so yes

B

7 0
3 years ago
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Radda [10]

x=x-12

x+x-12=50

2x=62

x=31

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3 years ago
The table below shows the distance y, in miles per minute, of a toy car at different times x, in minutes: Time (x) (minutes) 10
Mkey [24]
The answer is -0.04 for part A
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