To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate. So in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate.
To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate. So in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate.
Answer:
We have the sentence:
"X by the power of 5 times y to the power of 6 over 2 by the power of -2 times x by the power of 0times x by the power of 9"
Let's break it into parts.
"X by the power of 5 times y to the power of 6..."
This can be written as:
x^5*y^6
"... 2 by the power of -2 times x by the power of 0times x by the power of 9"
This can be written as:
2^(-2)*x^(0)*x^(9)
And we have the quotient between the first thing and the second thing, then the equation is:

And any number by the power of 0 is equal to 1, then:
x^0 = 1, then we can rewrite the equation as:

We can keep simplifying this.
We know that:
a^(-n) = (1/a)^(n)
Then:
2^(-2) = (1/2)^2 = 1/4
Then we get:

And we also know that:
a^n/a^m = a^(n - m)
Then:

And we can't simplify this anymore.
19.625cm squared because you have to divide the diameter by 2 to get the radius.
Area of circle = pi times radius times radius
= 3.14 times 2.5 times 2.5
= 19.625cm squared
Answer:
see below
Step-by-step explanation:
The rotation transformations are ...
90° : (x, y) ⇒ (-y, x)
180° : (x, y) ⇒ (-x, -y)
270° : (x, y) ⇒ (y, -x)
Applying these to the given points, you get ...
9) A'(6, 9)
10) A'(15, 11)
11) A'(9, 6)
12) A'(-11, 15)
13) A'(6, -9)
14) A'(15, -11)