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Nikitich [7]
3 years ago
14

How many 30 are there in 600

Mathematics
2 answers:
strojnjashka [21]3 years ago
5 0
The question that is asked is pretty straight forward. Only thing that needs to be found is the number of 30 in the number 600. By dividing 600 by 30 we can arrive at the desired result.
Number of 30 in 600 = 600/30
                                 = 60/3
                                 = 20
So there are 20 number of 30s in the number 600. This method can be used to find answers to several other similar kind of questions like the number of 10s in 1000.Following the same procedure we get
Number of 10 in 1000 = 1000/10
                                   = 100
Anna11 [10]3 years ago
5 0
If you think of the factors that make 600 you get 20 factors of 30 so your answer would be 20 
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Answer this question
Murljashka [212]

Answer:

a = p * q

b = p * s + q * r

c = r * s

Step-by-step explanation:

In the trinomial ax² + bx + c

a is the coefficient of x²

b is the coefficient of x

c is the numerical term

∵ The trinomial is ax² + bx + c

∵ Its factors are (px + r) and (qx + s)

∴ ax² + bx + c = (px + r)(qx + s)

∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)

∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs

∴ ax² + bx + c = pqx² + (ps + qr)x + rs

→ By comparing the two sides

∵ ax² = pqx² ⇒ divide both sides by x²

∴ a = pq

∵ bx = (ps + qr)x ⇒ Divide both sides by x

∴ b = ps + qr

∴ c = rs

∴ a = p * q

∴ b = p * s + q * r

∴ c = r * s

5 0
3 years ago
This month the Middle School Media newspaper has 25 pages. Twenty-five schools order the paper for each of their students. Each
EastWind [94]

Answer:

25 to the power of 3.

Step-by-step explanation:

we got 25 schools ordering newspapers for 25 classes of 25 kids. that's 25x25x25. it wants the number of pages total, and since there's 25 pages in each newspaper we add another 25. so it's 25x25x25x25, also known as 25 to the power of 3.

5 0
3 years ago
Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.
Sauron [17]

\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

5 0
3 years ago
What are the factors of the expression below? 4X2 + 12x +9
arsen [322]
D is the correct choice
7 0
3 years ago
Complete the expanded notation for 64,375
NISA [10]

There are several expanded forms for a decimal number. Pick the one that matches your requirements.

64,375 = 60,000 +4,000 +300 +70 +5

64,375 = 6×10,000 +4×1,000 +3×100 +7×10 +5×1

64,375 = 6×10⁴ +4×10³ +3×10² +7×10¹ +5×10⁰

3 0
3 years ago
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